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7 Jul 2007 15:24:55 IST
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Find the equation of circle which bisects the circumference of the circles x2+y2=1 ; x2+y2+2x=3 ; x2+y2+2y=3.....plz answer quickly with procedure ....i willl definetly give many rates to those who give correct answer..... THANK YOU....
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The only place where you will find success before hard work is in the dictionary
A winner never quits.....a quitter never wins......
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7 Jul 2007 15:37:37 IST
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nonne to answer this question????somebody plzzz answer time is running out.......plz relpy fast..........try to solve this question .....
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The only place where you will find success before hard work is in the dictionary
A winner never quits.....a quitter never wins......
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The centre of the required circle is the radial centre of the three given circles...
and the radius will be length of tangent from this point to any of the given circles..
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Keep working....................Iam comming..
your's only,
Success!! |
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7 Jul 2007 17:35:54 IST
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i have tried tht way rini ...we get the radical centre as (1,1) but in the answer...the centre of circle is (-2,-2) and radius is 3....i am not gettin it.....plz help me.......u plz solve and show ......
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The only place where you will find success before hard work is in the dictionary
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7 Jul 2007 17:51:37 IST
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will anybody plz asnwer........i am waitin from an hour.....plz reply somebody help..........
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The only place where you will find success before hard work is in the dictionary
A winner never quits.....a quitter never wins......
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7 Jul 2007 20:31:04 IST
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somebody help.....it so seems no one knows to solve this prob????where are the experts?????no one can solve and tell the procedure to solve the question?????plz help ,......
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The only place where you will find success before hard work is in the dictionary
A winner never quits.....a quitter never wins......
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7 Jul 2007 21:04:27 IST
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i find this question to be a good one can anyone help ananth_patri .......
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7 Jul 2007 21:08:22 IST
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ok so u have x2+y2=1 ----------------1 x2+y2+2x=3 ; ------------2 x2+y2+2y=3----------------3 as the eq of 3 circles let the given circle be x2+y2 + 2gx + 2fy +c=0 ---------4 4-1 we get the eq of the diameter of circle1 2gx+2fy+c+1=0 the diameter passes through its center (0,0) so 0+0+c+1=0 [c=-1] simlarly 4-2 2gx+2fy-1 -2x+3=0 passes through (-1,0) -2g-1+2+3=0 [g=2] again 4-3 4x+2fy-1-2y+3=0 passes through (0,-1) -2f-1+2+3=0 [f=2] hence the eq of the circle is x2+y2 +4x+4y-1=0 hope my caculations are right, but the methord is correct. plz correct me if wrong
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if u notice this notice u will notice that this notice is not worth noticing! |
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7 Jul 2007 21:10:42 IST
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U R PERFECTLY RIGHT ASHWIN THANKKKKKYOUUU VERY MUCH..........IT NEVER OCCURED TO ME TO DO BY COMMON CHORD(DIAMETRE HERE ).......THANXXX
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The only place where you will find success before hard work is in the dictionary
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7 Jul 2007 21:13:55 IST
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i agreee with your answer a5hw1n_5 good job....take my rate...
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