if 4a+2b+c=0 then the equation 3ax^2+2bx+c has atleast one real root lying between a)0 and 1 b)

aal izz well

if 4a+2b+c=0 then the equation 3ax^2+2bx+c has atleast one real root lying between a)0 and 1b)1 and 2c)0 and 2d)none of these

~~~iShAli~~~

If we integrate the given expression,i.e. 3ax²+2bx+c we get ax³+bx²+cx

applying limits frm 0 to 2 we find that the value of integeral is 2(4a+2b+c) which is 0

this means that the area under curve of the given expression is 0 b/w 0and2 so the curve of the given expression will have to intersect the x axis in this interval.....so there will be a root in the interval (0,2)

ans is (c)

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