two common tangebts to the circle x² + y² = a²/2 and the parabola  y² = 4ax  are

a) x = +-(y + 2a)

b) y = +-(x + 2a)

c) x = +-(y + a)

d) y = +-(x + a)

Please show the solution also.

 Tangent for slope m is given by:-

y=mx+a/m (For parabola)

y=mx+a(1+m^2)^1/2/root2

so equate the constant term

u will get

m^2(1+m^2)=2

solving u will get

m^2=1

M=+1,-1

hence u will get two tangents