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Ask community Community Discussion Question: The points (0,8/3),(1,3)&(82,30) rthe verticesofa)noneb)obtusec)isoscelesd)acute
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jay (64)

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The points (0,8/3),(1,3)&(82,30) rtheverticesofa)noneb)obtusec)isoscelesd)acute
    
jay (64)

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When we find there determinant we get 0 these proves they are collinear but when we take there slops two at a time then they dont come out to be equal showing they are noncollinear so what should i do?
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Yagyadutt Mishra (5422)

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 This is because they are not forming triangles.... 

 

slope  when you take  (1,3) and (0,8/3) comes equal to 1/3 

 

when take  ( 82,30) and (1,3)  comes equal to 1/3 

 

means all three are collinear with 1/3 at starting point

More explanation:-

 

First of all 

 

Don't panic after seeing big values of co-ordinate....because they are arranged in such manner..that you can easily solve it....many term will be canceled out ...

 

 

A ( 0,8/3 )                                  B(1,3)                                    C ( 82,30) 

 

Slope of AB   =  (3-8/3)/(1-0)  =  1/3 

 

Slope of   CB =  (30-3)/(82-1) = 27/81 = 1/3 

 

And it is not possible that two side in a triangle has same slope.....so obviously this co-ordinate is not forming any triangle,,,:D


Life is a game ...and the only way to win it ..is don't play :D
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