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25 Jul 2007 15:53:29 IST
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Q.Let p{sin ,cos }where 0 2 be a pt nd let oab be a triangle with vertices{0,0},{ 3/2 , 0} nd {0, 3/2}.find if p lies inside the OAB. experts plzzz reply i need ur help... plzz make ur answer clear...
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25 Jul 2007 16:14:30 IST
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is less than or equal to 2 .....is it......
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The inevitable truth of life.....everyone in our life is going 2 hurt sooner or later......u just have 2 realise who is worth.....
the PAIN or the PERSON...!!! |
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25 Jul 2007 16:17:25 IST
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listen find the equation of the line joining A n B.....p must lie on the same side of origin......then p n A lie on the same side of the X-axis(considering A as(0,root3/2)......then again p n B lie on the same side of Y-axis........substitute n get the answer..............
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The inevitable truth of life.....everyone in our life is going 2 hurt sooner or later......u just have 2 realise who is worth.....
the PAIN or the PERSON...!!! |
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try it
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The inevitable truth of life.....everyone in our life is going 2 hurt sooner or later......u just have 2 realise who is worth.....
the PAIN or the PERSON...!!! |
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25 Jul 2007 17:01:11 IST
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hey i got it as origin o &p lie on the same side so sin{  +45} <  /3 thank u verry much u deserve a salute
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27 Jul 2007 19:25:48 IST
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c first calc the equns of all the 3 lines then put the value of the coord of the pt. opp to that line in the eqn. n check the value (that is wether it is +ve or -ve) then put coord of p in the same eqn and then form the inequality repeat it fr all the other eqns. u will get the ans.
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