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6 Jul 2007 21:42:53 IST
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Prove that a triangle having integral coordinates cannot be an equilateral triangle.
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-RAhul |
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6 Jul 2007 21:49:31 IST
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let the coordinates of the triangle be (a,b) , (c,d) , (e,f) let us assume the triangle is equilateral with a side length 'l' .
now the area of triangle(A) = 1/2 | a(d-f) + c(f-b) + e(b-d) |
if the coordinates area intergral then A is integral(rational).
whereas the area of an equilateral triangle is also given by(A') = sqrt(3)/4 (l)^2
now A = A' here, LHS is rational but RHS is irrational (bcoz' of root(3) ) wich is not possible. so, the equilateral triangle cannot have integral coordinates..
plz correct me if i'm wrong anywhere...
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7 Jul 2007 16:13:53 IST
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From the knowledge of coordinate geometry :
Area of triangle = (1/2)|x1(y2-y3) + x2(y3-y1) + x3(y1-y2)|
If the coordinates are integral then the area would also be an integer.
(Side of equilateral triangle)2 , a2 = (y2-y1)2 + (x2-x1)2 which is also an integer.
Area = ( 3)a2/4 which is irrational.
This is a contradiction.
So, an equilateral triangle cannot have integral coordinates.
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Bipin Kumar Dubey
Chemical Dept.
IIT Kharagpur
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