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4 Feb 2012 19:46:17 IST
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Integrate (0 to 2) dx / (1-x)^2
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4 Feb 2012 21:30:45 IST
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2?
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4 Feb 2012 21:34:28 IST
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TRAP!!
Had it been an objective type question, you could get a negative mark....
It is wrong...
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4 Feb 2012 21:37:09 IST
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why? its an area,so it has to be positive right?
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4 Feb 2012 21:42:50 IST
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oh yes, :D i fell for the trap,my above query gave my answer..
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4 Feb 2012 21:55:45 IST
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I will reveal the answer if someone gives the right answer or atleast 5 people try and don't get it...
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4 Feb 2012 22:51:00 IST
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the function is discontinuous at x=1
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4 Feb 2012 23:48:41 IST
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V cnt define it at 1,so v cnt integrate
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5 Feb 2012 18:43:49 IST
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Yeah, the integral is not defined because of discontinuity.
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6 Feb 2012 16:23:40 IST
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so the answer is not defined rite???
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6 Feb 2012 18:46:33 IST
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Actually the area under the curve comes out to be infinity in the given interval. We may say the answer is +infinity.
Google this:
y=1/(x-1)^2
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