find the max area of an isosceles triangle inscribed in a standard ellipse with its vertex at one en

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15 Mar 2009 21:21:20 IST

Subject: find the max area of an isosceles triangle inscribed in a standard ellipse with its vertex at on

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clearly from figure,

area of tri. ABC = $A=ab(sin\alpha-\frac{sin2\alpha}{2})$

for max area A'=0,we get,

cos@ = -0.5 => @ = 120⁰

so,

$A_{max}=\frac{3\sqrt{3}ab}{4}$

all's well that end's well, but if it dosen't, then it is not the end . . .

this reply: 4 points (with 0 Olaaa!! Perrrfect answer.

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